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The energies `E_1` and `E_2` of two radiations are `25 eV` and `50 e V` respectively. The relation between their wavelengths, i.e., `lamda_1` and `lamda_2` will be.A. `lamda = lamda_2`B. `lamda_1 = 2 lamda_2`C. `lamda_1 = (1)/(2) lamda_2`D. `lamda_1 = 4 lamda_2` |
Answer» Correct Answer - B (b) `E_1 = (hc)/(lamda_1)` and `E_2 = (hc)/(lamda_2)` `:. (E_1)/(E_2) = (lamda_2)/(lamda_1)` `(25)/(50) = (lamda_2)/(lamda_1)` `:. lamda_1 = 2 lamda_2`. |
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