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The energies `E_1` and `E_2` of two radiations are `25 eV` and `50 e V` respectively. The relation between their wavelengths, i.e., `lamda_1` and `lamda_2` will be.A. `lambda_1=1/2 lambda_2`B. `lambda_1 =lambda_2`C. `lambda_1 = 2lambda_2`D. `lambda_1=4lambda_2`

Answer» Correct Answer - C
`lamda_1=2lambda_2`


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