1.

The energy in `MeV` is released due to transformation of `1 kg` mass completely into energy `(c = 3 xx 10^8 m//s)`.A. `7.625 xx 10 Mev`B. `10.5 xx 10^29 MeV`C. `2.8 xx 10^-28 MeV`D. `5.625 xx 10^29 MeV`

Answer» Correct Answer - D
(d) `E = Delta mc^2 = 1 xx (3 xx 10^8) = 9 xx 10^10 J`
`rArr E = (9 xx 10^16)/(1.6 xx 10^-19) = 5.625 xx 10^35 eV`
=`5.625 xx 10^29 MeV`.


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