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The energy liberated on complete fission of `1 kg` of `._92 U^235` is (Assume `200 MeV` energy is liberated on fission of `1` nucleus).A. `8.2 xx 10^10 J`B. `8.2 xx 10^9 J`C. `8.2 xx 10^13 J`D. `8.2 xx 10^16 J` |
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Answer» Correct Answer - C ( c) Mass of a uranium nucleus =`92 xx 1.6725 xx 10^-17 + 147 xx 1.6747 xx 10^-27` =`393.35 xx 10^-27 kg` Number of nuclei in the given mass =`(1)/(393.35 xx 10^-17) = 2.542 xx 10^24` Energy released `= 200 xx 2.542 xx 10^24 MeV` =`5.08 xx 10^26 MeV = 8.135 xx 10^13 J ~~ 8.2 xx 10^13 J`. |
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