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The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of excited state(s) for the electron in the Bohr orbit of hydrogen is(are)A. `-3.4eV`B. `4.2eV`C. `-6.8 eV`D. `+6.8eV` |
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Answer» Correct Answer - A `E_(n) =- (13.6)/(n^(2))ev//"atom"` |
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