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The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of exxcited state(s) for the electron in the Bohr orbit of hydrogen is//areA. `-3.4 eV`B. `-4.2 eV`C. `6.8 eV`D. `+6.8 eV` |
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Answer» `E_(n) = (-13.6)/(n^(2))eV` when `n =2,E_(2) =(-13.6)/(4) = 3.4 eV` Hence (a) is the correct answer |
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