1.

The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of exxcited state(s) for the electron in the Bohr orbit of hydrogen is//areA. `-3.4 eV`B. `-4.2 eV`C. `6.8 eV`D. `+6.8 eV`

Answer» `E_(n) = (-13.6)/(n^(2))eV`
when `n =2,E_(2) =(-13.6)/(4) = 3.4 eV`
Hence (a) is the correct answer


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