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The energy of an electron in the first Bohr orbit of H atom is `-13.6 eV` The potential energy value (s) of excited state(s) for the electron in the Bohr orbit of hydrogen is(are)A. `- 3.4 eV`B. `4.2 eV`C. `-6.8 eV`D. `+ 6.8 eV` |
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Answer» Correct Answer - A Eecited state is given as `= (-13.6 eV)/(n^(2))` `e.g. n = 2 ,E = (-13.6)/(4) = - 13.6 eV` |
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