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The energy of one quantum of light with a wavelength of `6500Å(1Å = 10^(-10)` cm)A. `9.04xx10^(-24)` JB. `3.02xx10^(-20)` JC. `3.06xx10^(-19)` JD. `6.02xx10^(-20)` J |
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Answer» Correct Answer - C `E=hv=(hc)/lambda=(6.625xx10^(-34)xx3xx10^(8))/(6500xx10^(-10))` `E=3.06xx10^(-19)` J |
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