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The energy released by the fission of a single uranium nucleus is `200 MeV`. The number of fission of uranium nucleus per second required to produce `16 MW` of power is (Assume efficiency of the reactor is `50%`)A. `2xx10^(6)`B. `2.5xx10^(6)`C. `5xx10^(6)`D. `1xx10^(18)` |
Answer» Correct Answer - D No of fission = total energy produced/(energy released per fission `xx` efficiency) |
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