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                                    The equation `|2ax-3|+|ax+1|+|5-ax|=(1)/(2)` possessesA. Infinite number of real solutions for some `a in R`B. finitely many real solutions for some `a in R'`C. no real solutions for some `a in R`D. no real solutions `a in R` | 
                            
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Answer» Correct Answer - D `(d)` We have `|2ax-3|+|ax+1|+|5-ax|=(1)/(2)` Now `|2ax-3|+|ax+1|+|5-ax| ge |2ax-3-(ax+1)+5-ax|=1` So the given equation has no solution.  | 
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