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The equation `asinx+Cos2x=2a-7` possesses a solution if |
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Answer» Given equation is, `asinx + cos2x = 2a-7` `=>asinx+1-2sin^2x =2a - 7` `=>2sin^2x-asinx+2a-8 = 0` `=> sinx = (-(-a)+-sqrtD)/(2(2))` Here, `D = (-a)^2-4(2)(2a-8)` `=> D = a^2-16a+64 = (a-8)^2` `:. sinx = (a+-(a-8))/4` As `sin x` lies between `-1` and `1`. `:. sin x = (a+(a-8))/4` `=>sinx = (a-4)/2` `:. -1 le (a-4)/2 le 1`. `=>-2 le a-4 le 2` ` => 2 le a le 6` So, for `2 le a le 6`, given eqaution will possess a solution. |
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