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The equation of a wave travelling on a string is `y=(0.10mm)sin[3.14m^-1)x+(314s^-1)t]`. (a) In which direction does the wave travel ? (b) Find the wave speed, the wavelength and the frequency of the wave. (c) What is the maximum displacement and the maximum speed of a portion of the string ? |
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Answer» Correct Answer - A::B::C::D The equation of the wave is given by `y=[(01 mm)sin(314m^-1)x+(31.4s^-1)t]` `y=rsin{((2pix)/lamda)+omegat}` a. Negative x -direction ltbr. b.`k=31.4m^-1` `rarr (2pi)/lamda=31.4` `rarr lamda=(2pi)/31.4=0.2m=20cm` Again `w=314s^-1` `rarr 2pif=314` `rarr f=314/(2pi)` `=314/(2xx3.14)` `=50sec^1=50Hz` wave speed `v=lamdaf=20xx50` `=1000cm/s` `c. Max displacement =0.10mm `Max. velocity =`aw=0.1xx10^-1xx314` `=3.14cm/sec` |
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