1.

The equation of motion of a particle executing simple harmonic motion is `a+16pi^(2)x = 0` In this equation, a is the linear acceleration in `m//s^(2)` of the particle at a displacement x in meter. The time period in simple harmonic motion isA. `(3)/(4)sec`B. `(1)/(2)sec`C. `1sec`D. `2 sec`

Answer» Correct Answer - B
`a = -16 pi^(2) s`
standared equation of `SHM` is
`A = - omega^(2) s`
Hence camparing two equatios, we get
`omega = 4 pi`
`T = (2pi)/(omega) = (2 pi)/(4 pi) = (1)/(2) sec`


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