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The equation of motion of a particle executing simple harmonic motion is `a+16pi^(2)x = 0` In this equation, a is the linear acceleration in `m//s^(2)` of the particle at a displacement x in meter. The time period in simple harmonic motion isA. `(3)/(4)sec`B. `(1)/(2)sec`C. `1sec`D. `2 sec` |
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Answer» Correct Answer - B `a = -16 pi^(2) s` standared equation of `SHM` is `A = - omega^(2) s` Hence camparing two equatios, we get `omega = 4 pi` `T = (2pi)/(omega) = (2 pi)/(4 pi) = (1)/(2) sec` |
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