The equation of the line passing through the point (1, 2) and perpendi

1.	The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 isA. y – x + 1 = 0B. y – x – 1 = 0C. y – x + 2 = 0D. y – x – 2 = 0
Answer» B. y – x – 1 = 0 Explanation: Given that line passing through the point (1, 2) And perpendicular to the line x + y + 1 = 0 Let the equation of line ‘L’ is x – y + k = 0 … (i) Since, L is passing through the point (1, 2) ∴ 1 – 2 + k = 0 ⇒ k = 1 Putting the value of k in equation (i), we get x – y + 1 = 0 Or y – x – 1 = 0 Hence, the correct option is (b)

The equation of the line passing through the point (1, 2) and perpendicular to the line x + y + 1 = 0 isA. y – x + 1 = 0B. y – x – 1 = 0C. y – x + 2 = 0D. y – x – 2 = 0

Answer»

B. y – x – 1 = 0

Explanation:

Given that line passing through the point (1, 2)

And perpendicular to the line x + y + 1 = 0

Let the equation of line ‘L’ is

x – y + k = 0 … (i)

Since, L is passing through the point (1, 2)

∴ 1 – 2 + k = 0

⇒ k = 1

Putting the value of k in equation (i), we get

x – y + 1 = 0

Or y – x – 1 = 0

Hence, the correct option is (b)