1.

The equation of the straight line passing through the point (3, 2) and perpendicular to the line y = x is(A) x – y = 5 (B) x + y = 5(C) x + y = 1 (D) x – y = 1

Answer»

Answer is (B)

Slope of the given line y = x is 1.

Thus, slope of line perpendicular to y = x is -1.

Line passes through the point (3, 2).

So, equation of the required line is:y-2=-l (x – 3) => x + y = 5



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