1.

The equation `tan^4x-2sec^2x+a=0`will have at least one solution if

Answer» `tan^4x-2sec^2x +a = 0`
`=>tan^4x-2(1+tan^2x) +a = 0`
`=>tan^4x-2tan^2x -2 +a = 0`
`=>tan^4x-2tan^2x +1-3 +a = 0`
`=>(tan^2x - 1)^2 = 3-a`
To have at least one solution for this equation,
`3-a ge 0`
`=>a le 3`
So, option `c` is the correct option.


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