1.

The equivalent resistance between points A and B in the following electric circuit is ……………… .

Answer»

`2.5 Omega`
`5 Omega`
`12.5 Omega`
`20 Omega`

Solution :Resistors `R_1 and R_2` are CONNECTED in PARALLEL.
`:. R. = (R_1 R_2)/(R_1 + R_2) = (5 xx 5)/(5 + 5) = 2.5 Omega`
Now, `R., R_3 and R_5` are connected in series
`:. R = R.+ R_3 + R_5`
`=2.5 + 5 + 5 = 12.5 Omega`


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