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The excitation energy of first excited state of a hydrogen like atom is `40.8 eV`. Find the energy needed to remove the electron to form the ion. |
Answer» Correct Answer - `54.4 eV` `40.8=(Delta E)_(2 to 1)xxZ^(2) rArr 40.8=10.2xxZ^(2) rArr z^(2)=4 "or" Z=2` `IE=13.6 Z^(2)=13.6xx4=54.4 eV` |
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