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The expression `3[sin^4(3/2pi-alpha)+sin^4(3pi+alpha)]-2[sin^6(1/2pi+alpha)+sin^6(5pi-alpha)]` is equal to |
Answer» Correct Answer - B `3[sin^4(3/2pi-alpha)+sin^4(3pi+alpha)]` `-2[sin^6(1/2pi-alpha)+sin^6(5pi-alpha)]` `=3(cos^4alpha+sin^4alpha)-2(cos^6alpha+sin^6alpha)` `3(1-2sin^2alphacos^2alpha)-2[(sin^2alpha+cos^2alpha)^3` `-3sin^2alphacos^2alpha(sin^2alpha+cos^2alpha)]` `=3(1-2sin^2alphacos^2alpha)-2[1-3sin^2alphacos^2alpha]` =1 |
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