The expression A+BC is thereduced form of ______________(a) AB+BC(b) (A+B)(A+C)(c) (A+C)B(d) (A+B)CThis question was posed to me during an interview.This is a very interesting question from SOP & POS topic in division Boolean Algebra and Logic Circuits of Computer Fundamentals

The expression A+BC is thereduced form of ______________(a) AB+BC(b) (

1.	The expression A+BC is thereduced form of ______________(a) AB+BC(b) (A+B)(A+C)(c) (A+C)B(d) (A+B)CThis question was posed to me during an interview.This is a very interesting question from SOP & POS topic in division Boolean Algebra and Logic Circuits of Computer Fundamentals
Answer» The CORRECT CHOICE is (b) (A+B)(A+C) Easy explanation: The SECOND OPTION is correct. It can simplified as FOLLOWS: (A+B)(A+C) =AA+AC+AB+BC =A+AC+AB+BC =A(1+C)+AB+BC =A+AB+BC =A(1+B)+BC =A+BC.

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The expression A+BC is thereduced form of ______________(a) AB+BC(b) (A+B)(A+C)(c) (A+C)B(d) (A+B)CThis question was posed to me during an interview.This is a very interesting question from SOP & POS topic in division Boolean Algebra and Logic Circuits of Computer Fundamentals

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