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The expression of current flowing in a series equalizer is?(a) Vmax/√((Ro)^2+(X1)^2)(b) Vmax/√((2Ro)^2+(X1)^2)(c) Vmax/√((2Ro)^2+(2X1)^2)(d) Vmax/√((Ro)^2+(2X1)^2)I got this question at a job interview.Enquiry is from Series Equalizer topic in portion Filters and Attenuators of Network Theory

Answer»

The CORRECT option is (c) Vmax/√((2Ro)^2+(2X1)^2)

The best explanation: When the equalizer is connected, the EXPRESSION of CURRENT flowing in a series equalizer is I1 = Vmax/√((2Ro)^2+(2X1)^2) where Vmax is voltage applied to the network and Ro is RESISTANCE of the load as well as source and 2X1 is the reactance of the equalizer.



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