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The expression of ωr in a parallel resonant circuit is?(a) 1/(2√LC)(b) 1/√LC(c) 1/(π√LC)(d) 1/(2π√LC)The question was posed to me in an interview for job.I need to ask this question from Resonant Frequency for a Tank Circuit in chapter Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

The correct answer is (B) 1/√LC

Easy explanation: The stored energy is transferred back and forth between the capacitor and coil and vice-versa. The expression of ωr in PARALLEL RESONANT circuit is ωr = 1/√LC.



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