InterviewSolution
Saved Bookmarks
| 1. |
The figure shows elliptical orbit of a planet m about the sun S. the shaded area SCD is twice the shaded area SAB. If t_(1) be the time for the planet to move from C to D and t_(2) is the time to move from A to B, then: |
|
Answer» SOLUTION :According to KEPLER's `II^(nd)` law, AREA VELOCITY for the palnet is constant `:. ""(A_1)/(t_1)= (A_2)/(t_2), A_1=2A_(2)` `:. ""(2A_2)/(t_1)= (A_2)/(t_2)` `t_1= 2t_2`. |
|