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The focal distance of a point on the parabola `y^2=12 xi s4.`Find the abscissa of this point.A. 1B. `-1`C. `2sqrt2`D. `-2`

Answer» Correct Answer - A
Focal distance of a point `(x_(1), y_(1))` on the parabola is `y^(2)=4ax` is equal distance from directrix x+a=0 is
`x_(1)+a`
`"For "y^(2)=12x,` comparing with `y^(2)=4ax`.
`4a=12rArra=3`
`"so, "x_(1)+2=4`
`rArr" "x_(1)=1`


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