1.

The freezing point depression of a 0.10 m solution of HF (aq) solution is -0.201 °C. Calculate the percent dissociation of HF (aq).

Answer»

ΔTf = i x Kf x m

0.201 = i x 1.86 x 0.1

i = 0.201/0.186 = 1.08

α = (i-1)/( n-1)

=1.08 – 1 = 0.08

% dissociation of HF is 8%



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