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The freezing point (in `.^(@)C)` of a solution containing `0.1 g` of `K_(3)[Fe(CN)_(6)]` (Mol.wt. 329) in 100 g of water `(K_(f) = 1.86 K kg mol^(-1))` isA. `-2.3 xx 10^(-2)`B. `-5.7 xx 10^(-2)`C. `-5.7 xx 10^(-3)`D. `-1.2 xx 10^(-2)` |
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Answer» Correct Answer - A `DeltaT_(f) = m xx K_(f) xx i` `=(0.1//329)/(100) xx 1000 xx 1.86 xx 4 = 0.2261` `= 2.3 xx 10^(-2)` `T_(f) = 0 - DeltaT_(f) =- 2.3 xx 10^(2).^(@)C` |
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