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The freezing point (`"in"^(@)"C"`) of a solution containing 0.1 g of `K_(3)[Fe(CN)_(6)]` ( Mol. Wt. 329) in 100g of water (`K_(f)"=1.86 k kg mol"^(-1))` isA. `-2.3xx10^(-2)`B. `-5.7xx10^(-2)`C. `-5.7xx10^(-3)`D. `4.0xx10^(-6)` |
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Answer» Correct Answer - A `"For" K_(3)[Fe(CN)_(6)]i=4` `DeltaT_(f)=ixx(K_(f)W_("solute")xx1000)/(m_("solute")xxw_("solvent"))` `DeltaT_(f)=4xx1.86xx(0.1xx1000)/(329xx100)` `thereforeT_(f)("solution")=0.0023=-2.3xx10^([email protected])"C"` |
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