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The freezing point of a `0.05` molal solution of a non-electrolyte in water is: (`K_(f) = 1.86 "molality"^(-1)`)A. `-1.86^(@)C`B. `-0.93^(@)C`C. `-0.093^(@)C`D. `0.93^(@)C` |
Answer» Correct Answer - C As we know ,the depression in freezing point is `DeltaT_(f)=K_(f)xx i xx "molarity"` From question,molal concentration ` = C _(m)=0.05m` for, non-electrolytes,`i=1 K_(f)=1.86` `:. DeltaT_(f)=1.86xx1xx0.05=0.0930^(@)C` hence, F.P.of solution `=0-0.093^(@)C=-0.093^(@)C` |
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