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The freezing point of a pure solvent is 315 K. On addition of 0.5 mole of urea in 1 kg of the solvent, the freezing point decreases by 3 K. Calculate the molal depression constant for the solvent. |
Answer» Given : m = Molality of urea = 0.5 m ΔTf = Depression in the freezing point = 3 K K = Molal depression constant for the solvent = ? ΔTf = Kf × m ∴ Kf = \(\frac{ΔT_f}{m}\) = \(\frac{3}{0.5}\) = 6 K kg mol-1 ∴ Molal depression constant = 6 K kg mol-1 |
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