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The freezing point of benzene decreases by `0.45^(@)C` when 0.2 g of acetic acid is added to 20 g of benzene. If acetic acid associates of form a dimer in benzene, percentage association of acetic acid in benzene will be `(K_(f)"for benzene"=5.12 "K kg " mol^(-1))`.A. 0.746B. 0.946C. 0.646D. 0.804 |
Answer» Correct Answer - b `"Molality (m)"=("No.of moles of "CH_(3)COOH)/("Mass of benzene in kg")` `((0.2))/((60 g mol^(-1))xx(0.02kg))` `=0.167 mol kg^(-1)=0.167m` `DeltaT_(f)=ixxK_(f)xxm or i=(DeltaT_(f))/(K_(f)xxm)` `i=((0.45K))/((5.12 "K kg mol"^(-1))xx(0.167"mol kg "^(-1)))=0.526` `alpha=((i-1))/((n-1))=((0-526-1))/((0.5-1))` `=((-0474))/((-0.5))=0.948 %` |
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