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The frequency corresponding to transition `n = 1` to `n = 2` in hydrogen atom is.A. `15.66xx10^10` HzB. `24.66xx10^14` HzC. `30.57xx10^14` HzD. `40.57xx10^24` Hz

Answer» Correct Answer - B
`barv=1/lambda=R[1/n_1^2-1/n_2^2]=109678[1/1-1/4]=82258.5`
`lambda=1.21567xx10^(-5)` cm or `lambda=12.1567xx10^(-6)` cm
`=12.1567xx10^(-8)` m
`v=c/lambda=(3xx10^8)/(12.1567xx10^(-8))=24.66xx10^14` Hz.


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