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The function f(x), for which `f(x)={x^(2),xne1 2, x=1}` Show that: `lim_(x to 1) f(x)=1` |
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Answer» At `x=1 ` R.H.L. `=underset(xrarr1+)"lim"f(x)=underset(hrarr0)"lim"f(1+h)` `=underset(hrarr0)"lim"(1+h)^(2)=(1+0)^(2)=1` L.H.L. `=underset(xrarr1-)"lim" f(x)=underset(hrarr0)"lim"f(1-h)` `=underset(hrarr0)"lim"(1-h)^(2)=(1-0)^(2)=1` `because R.H.L. =L.H.L.=1` `therefore underset(xrarr1)"lim"f(x)=1`. Hence Proved. |
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