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    				| 1. | The function `f(x)=(ln(pi+x))/(ln(e+x))`isincreasing in `(0,oo)`decreasing in `(0,oo)`increasing in `(0,pi/e),`decreasing in `(pi/e ,oo)`decreasing in `(0,pi/e),`increasing in `(pi/e ,oo)`A. increasing in `(0,oo)`B. decreasing oin `(0,oo)`C. increasing in `(0,pi//e),decreasing in(pi//e,oo)`D. decreasing in `(0,pi//e)` increasing in `(pi//e,oo)` | 
| Answer» Correct Answer - 2 `f(X)=(log(e+x)xx(1)/(pi+x)-log(pi+x)(1)/(e+x))/(log(e+x))^(2)` `=(log(e+x)xx(e+x)-(pi+x)log(pi+x))/(pi+x)(e+x)(log(e+x))/6(2)` Since log function is an increasing function and `eltpi` `log(e+x)ltlog(pi+x)` Thus `(e+x)log(e+x)lt(e+x)log(pi+x)lt(log(pi+x)` for all `x gt 0` Thus f(x)=0 ltrbgt Therefore f(X) decrease on `(0,oo)` | |