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The function `f(x)=tan^(-1)(sinx+cosx)`is an increasing function in`(-pi/2,pi/4)`(b) `(0,pi/2)``(-pi/2,pi/2)`(d) `(pi/4,pi/2)`A. `(0,pi//2)`B. `(0,(pi)/(2))`C. `(-(pi)/(2),(pi)/(2))`D. `((pi)/(4),(pi)/(2))` |
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Answer» Correct Answer - 1 Here fX() =`tan^(-1) (sinx+cosx)` `therefore f(X)=(1)/(1+(sinx+cosx)^(2)(cosx-sinx)` `=(cosx-sinx)/(2+sin 2 x)` `for -(pi)/(2)ltxlt(pi)/(4),cos x gtsinx` Hence y = f(X) is increasing in `(-(pi)/(2),(pi)/(4))` |
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