1.

The gravitational field intensity at a point 10,000km from the centre of the earth is 4.8Nkg^(-1). The gravitational potential at that point is

Answer»

Solution :Gravitational intensity `=E= (GM)/(R^2)`
Gravitational potential `V= -(GM)/(R )`
`(V)/(E )= -R`
or `V= -ExxR`
or `V= -4.8xx10,000xx10^(3)= -4.8xx10^(7)J KG^(-1)`.


Discussion

No Comment Found