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The half - life of `^(215) At` is `100 mu , s.`The time taken for the radioactivity of a sample of `^(215) At` to decay to `1//16^(th)` of its initially value isA. `400mu sec`B. `6.3 mu sec`C. `40mu sec`D. `300mu sec` |
Answer» Correct Answer - A `A = A_(0)((1)/(2))^(n) rArr (A)/(A_(0))= ((1)/(2))^(n)` `(1)/(16) = ((1)/(2))^(4) = ((1)/(2))^(n)` `n = 4` `t = nT_(1//2) = 4xx100 = 400mu sec` |
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