1.

The half-life of `.^215At` is `100mus`. The time taken for the activity of a sample of `.^215At` to decay to `1/16th` of its initial value isA. `400 mu s`B. `6.3 mu s`C. `40 mu s`D. `300 mu s`

Answer» Correct Answer - a
`(1)/(16)=(1)/(2^(t/100))`
or `(1)/(2^(4))=(1)/(2^(t//100)) =4 =(t)/(100)`
or `t=400 m u s`.


Discussion

No Comment Found

Related InterviewSolutions