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The half life of a radio active substance is `6` hours. The amount of the substance undergone disintegration when `36 gms` of it undergoes decay for `18` hours isA. `31.5 gm`B. `4.5 gm`C. `18 gm`D. `9 gm` |
Answer» Correct Answer - A `W=(W_(0))/(2^(n)), n=3` |
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