

InterviewSolution
Saved Bookmarks
1. |
The half-life of a radioactive isotope is 3 hours. Value of its disintegration constant isA. 0.231 per hrB. 2.31 per hrC. 0.2079 per hrD. 2.079 per hr |
Answer» Correct Answer - A `k = (0.693)/(t_(1//2)) = (0693)/(3hr) = 0.231` per hr. |
|