1.

The half life of `C^(14)(lambda=2.31xx10^(-4)` per year) isA. `2xx10^(2)` yrB. `3xx10^(3)` yrC. `3.3xx10^(4)` yrD. `4xx10^(3)` yr

Answer» Correct Answer - B
Radio active decay is first order reaction
So `lambda =(0.69)/(t_(1//2)`
`t_(1//2)=(0.693)/(2.31xx10^(-4))yr`
`=0.3xx10^(4)`
`=3xx10^(3)yr`


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