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The half-life of `Co^(60)` is 7 years. If one g of it decays, the amount of the substance remaining after 28 years isA. 0.25 gB. 0.125 gC. 0.0625 gD. 0.50 g |
Answer» Correct Answer - C `n = (28)/(7) = 4, N = (N_(0))/(2^(n)), N = (1)/(2^(4)) = (1)/(16) = 0.0625 g` |
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