1.

The half-life of `K^40` is `1.30xx10^9` y. A sample if `1.00g` of pure `KCI` gives 160 counts `s^(-1)`.Calculate the relative abundance of `K^40`(fraction of `K^40`present ) in natural potassium .

Answer» Correct Answer - [0.12 %]


Discussion

No Comment Found

Related InterviewSolutions