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The half-life of radium is 16000 yr, after how much time will 1 g radium be reduced to 125 mg?A. 800 yrB. 1600 yrC. 3200 yrD. 4800 yr |
Answer» Correct Answer - d Given, `t_(1//2) = 1600 yr, N_(0) = 1 g, N = 125 mg = (125)/(1000)g` We know that, `N = N_(0)((1)/(2))^((t)/(t_(1//2)))` `(125)/(1000) = ((1)/(2))^(t//1600), (1)/(8) or ((1)/(2))^(3) = ((1)/(2))^(t//1600)` Hence, `(t)/(1600) = 3 or t = 3xx1600 = 4800 yr` |
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