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The half-life of radon is `3.8` days. Three forth of a radon sample decay in.A. `5.02` daysB. `15.2` daysC. `7.6` daysD. `11.4` days

Answer» Correct Answer - C
( c) Decayed fraction `= (3)/(4)`, so undecayed fraction `= (1)/(4)`
Now `(N)/(N_0) = ((1)/(2))^n rArr (1)/(4) = ((1)/(2))^n rArr n = 2`
`rArr t = n xx T_(1//2) = 2 xx 3.8 = 7.6 days`.


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