The half-life period of `._(53)I^(125)` is 60 days. What percent of radioactivity would be present after 180 daysA. 0.25B. `12.5%`C. 0.5D. 0.75

The half-life period of `._(53)I^(125)` is 60 days. What percent of ra

1.	The half-life period of `._(53)I^(125)` is 60 days. What percent of radioactivity would be present after 180 daysA. 0.25B. `12.5%`C. 0.5D. 0.75
Answer» Correct Answer - B `N = (N_(0))/(2^(n)) n = (180)/(60) = 3` `(N)/(N_(0)) = (1)/(2^(3)) rArr (N)/(N_(0)) xx 100 = (1)/(8) xx 100 = 12.5%`

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The half-life period of `._(53)I^(125)` is 60 days. What percent of radioactivity would be present after 180 daysA. 0.25B. `12.5%`C. 0.5D. 0.75

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