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InterviewSolution
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The half -life period of `._(84)Po^(210)` is 140 days. In how many days `1 g` of this isotope is reduced to `0.25 g`? |
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Answer» Original quantity of the isotope `(N_(0)) = 1 g` Final quantity of the isotope `N = 0.25 g` We know that, `N = ((1)/(2))^(n) N_(0)` So, `(1)/(4) = ((1)/(2))^(n) xx 1` or `((1)/(2))^(2) = ((1)/(2))^(2)` or `n = 2` Time taken `T = n xx t_(1//2) = 2 xx 140 = 280` days |
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