

InterviewSolution
Saved Bookmarks
1. |
The half-life period of a radioactive element is 140 day. After 560 days, 1 g of the element will reduce toA. `1//8 g`B. `1//16 g`C. `1//4 g`D. `1//2 g` |
Answer» Correct Answer - b Number of half-lives(n) = `("Total time")/(t_(1//2)) =(560)/(14) =4` Amount left `= ((1)/(2))^(n)xx"initial amount" = ((1)/(2))^(4)xx1g = (1)/(16) g` |
|