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The half-life period of Uranium is 4.5 billion years. After 90 billion years, the number of moles of Helium liberated from the following nuclear reaction will be `._(92)U^(238) rarr ._(90)Th^(234) + ._(2)He^(4)`A. 0.75 moleB. 1.0 moleC. 11.2 moleD. 22.4 mole |
Answer» Correct Answer - A `N = (N_(0))/(2^(n)) = N = (N_(0))/(2^(2)) = (1)/(4)` `:.` converted moles `= 1 - (1)/(4) = (3)/(4) = 0.75` |
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