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1. |
The heat capacity of a vessel is 300 cal `.^(@)C^(-1)` and the heat capacity of water contained in the vessel is also 300 cal `.^(@)C^(-1)`. How much heat (in joules) is required to raise the temperature of water in the vessel by `126^(@)F`? |
Answer» A rise in temeprature of `9^(@)C` is equal to a rise in temperature of `5.^(@)C`. `therefore`A rise in temperature of 126 `.^(@)F` is on the celsius scale equivalent to `126xx(5)/(9)=14xx5=70.^(@)C` quantity of heat required to raise the temperature of the vessel by `1.^(@)C=300cal` ltBrgt `therefore` Heat requried to raise its temperature by ltBrgt `70.^(@)C=70xx300=21000` cal. similarly heat required to raise the temperature of water by `70.^(@)C=70xx300=21000cal` `therefore` the total heat required `=(21000+21000)cal=42000cal` `=4200xx4.2=176.4kJ` |
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