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The highest excited state that an unexcited hydrogen atom can reach when they are bombarded with ` 12.2 eV` electron is : |
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Answer» Correct Answer - 3 `E_1=-13.6` eV After absorption of 12.2 eV energy =-1.4 eV Now `E_n=E_1/n^2 therefore n^2=(-13.6)/(-1.4) =9.71` `therefore n=3` |
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