1.

The highest excited state that an unexcited hydrogen atom can reach when they are bombarded with ` 12.2 eV` electron is :

Answer» Correct Answer - 3
`E_1=-13.6` eV
After absorption of 12.2 eV energy =-1.4 eV
Now `E_n=E_1/n^2 therefore n^2=(-13.6)/(-1.4) =9.71`
`therefore n=3`


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